Question:
a copper wire has diameter of 0.5 mm and resistivity of 1.6*10^-8 ohm meter what will be length of wire to make its resistance 10 ohms
Answer:
R = pl/a, where,
R= Resistance of the wire
p= specific resistance
l=length of the wire
a= area of cross section of the wire
With the given values,
A= 1.96349541*10^-7
p = 1.6*10^-8
R= 10
l=(10*1.96349541*10^-7) /(1.6*10^-8)
l=122.7m
Not what you are looking for? Go ahead and submit the question, we will get back to you.
